ppts.net
当前位置:首页>>关于先化简再求值括号x-1括号除以2除以x加1减一括回来...的资料>>

先化简再求值括号x-1括号除以2除以x加1减一括回来...

[3/(x+1)-(x+1)]÷(x²-4x+4)/(x+1) =(3-3x-3

1/3×(x+1)=1/7×(2x-3) 7(x+1)=3(2x-3) 7x+7=6x-9 7x-6

1/10÷(1/4x-1)=5 解:1/4x-1=1/10÷5 1/4x-1=1

(X-1)-(2X+4)=6-X, X-1-2X-4=6-X, -X-5=6-X, -5=6,

4x^2乘上括号x^2减二分之1x加一括回 =4x²x²

可以确定: 4y(y+1/2)+(x-2y)(x+2y+1) =4y²+2

1/2(1-x)=k+1 1-x=2k+2 x=-2k-1 3/4(x-1)-2/5(3x+2

X^2=(x一l)^2+25 0=-2x+1+25 2x=26 X=13

(x-1)=16 x-1=16 x=17

8X+12(5/3X+1/2)=8-2/3(6X-9) 8X+20X+6=8-4X-6 28X+4X

网站首页 | 网站地图
All rights reserved Powered by www.ppts.net
copyright ©right 2010-2021。
内容来自网络,如有侵犯请联系客服。zhit325@qq.com