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解下列方程:(1)x2+4x-5=0 (2)(2x-3)2-5(...

(1)2x2-4x-3=0,2x2-4x=3,x2-2x=32,配方得:x2-2x+1=32+1,(x-1)2=52,开方得:x-1=±52,x1=1+102,x2=1-102. (2)x(2x+3)=5(2x+3),x(2x+3)-5(2x+3)=0,(2x+3)(x-5)=0,2x+3=0,x-5=0,x1=-32,x2=5.(3)x2-32x+2=0,b2-...

(1)分解因式得:(x-5)(x+1)=0,x-5=0,x+1=0,x1=5,x2=-1;(2)移项得:(x-3)2-(x+3)(x-3)=0,(x-3)(x-3-x-3)=0,-6(x-3)=0,x-3=0,x=3.

(1)去括号得:5x-25+2x-24=0,移项合并得:7x=49,解得:x=7;(2)去括号得:4x+3=2x-2+1,移项合并得:2x=-4,解得:x=-2;(3)方程整理得:0.7+3x?22=15?50x5,去分母得:7+15x-10=30-100x,移项合并得:115x=33,解得:x=33115;(4)去...

(1)∵x 2 -4x=-1,∴x 2 -4x+4=3,∴(x-2) 2 =3,∴x-2=± 3 ,∴x 1 =2+ 3 ,x 2 =2- 3 ;(2)方程变形得3x 2 +10x+5=0,∵a=3,b=10,c=5,∴b 2 -4ac=10 2 -4×3×5=40,∴x= -10± 40 2×3 ,∴x 1 = -5+ 10 3 ,x 2 = -5- 10 3 ;(3)∵3(x-5) 2 ...

(1)方程变形得:x2-4x=-1,配方得:x2-4x+4=3,即(x-2)2=3,开方得:x-2=±3,解得:x1=2+3,x2=2-3;(2)方程变形得:3(x-4)+2x(x-4)=0,分解因式得:(2x+3)(x-4)=0,解得:x1=-1.5,x2=4;(3)方程变形得:(x+2)2=2516,开方得...

1,根据韦达定理,令a=2,b=—4,c=—1

(1)196x2-1=0,整理,得(14x+1)(14x-1)=0,令14x+1=0或14x-1=0,解,得x1=-114,x2=114.(2)4x2+12x+9=81整理,得x2+3x-18=0,即:(x+6)(x-3)=0令x+6=0或x-3=0,解,得x1=-6,x2=3.(3)x2-7x-1=0即:x=7±72+42=7±532,∴x1=7+532,...

就这 1 个方程 ? 肯定有非零解。 5x1 = 2x2-4x3+3x4 取 x2 = 5, x3 = x4 = 0, 得基础解系 (2, 5, 0, 0)^T 取 x3 = -5, x2 = x4 = 0, 得基础解系 (4, 0, -5, 0)^T 取 x4 = 5, x2 = x3 = 0, 得基础解系 (3, 0, 0, 5)^T 则通解即一般解是 x = k1 (...

(1)x2+4x-2=0,x2+4x=2,x2+4x+4=2+4,(x+2)2=6,x+2=±6,x1=-2+6,x2=-2-6; (2)x2+3x+1=0,b2-4ac=32-4×1×1=5,x=?3±52,x1=?3+52,x2=-3+52;(3)4(x+1)2=(x-5)2,2(x+1)=±(x-5),2x+2=x-5,2x+2=-x+5,x1=-7,x2=1; (4)x+...

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