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解方程,要写过程,要全写完才采纳 (3x-1.5x)=10...

3x+1.5x*3=300 解 3x+2x=300 5x=300 x=60 望采纳!

解方程: 1)解:7x-2.5x+3x-1.5x=15×4-6×3 (7-2.5+3-1.5)x=60-18 6x=42 x=7 2)解:x/ 2+3/2x=7 (1/2+3/2)x=7 2x=7 x=3.5 3)解:6x-7=4x-5 6x-4x=7-5 2x=2 x=1 4)解:6(1/2-4)+2x=7-(1/3x-1) 6×1/2-6×4+2x=7-1/3x+1 3-24+2x=8-1/3x 2...

等于0.05

1.5x+18=3x 1.5x=18 x=12 回答完毕~ 有疑问请追问,我一定尽快回复你~ 无疑问请点击【采纳】,同时预祝学习进步~\(^o^)/~ 我不是学霸,叫我赌神~\(^o^)/~~\(^o^)/~~\(^o^)/~~\(^o^)/~

1)1.5x+3x=6 4.5x=6 x=6/4.5 =4/3 2)2x-1.5x=1.9 0.5x=1.9 x=1.9/0.5 =3.8 3)0.54 x-4.5*6=45 0.54x-27=45 0.54x=45+27=72 x=72/0.54 =400/3 4)7x-0.4=0.3 7x=0.3+0.4=0.7 x=0.7/7 =0.1 5)8x+5x=65 13x=65 x=65/13 =5 6)0.9x-3*1.2=7.2...

1.5x=3.6 x=2.4

2.8 +3x=7.6 解:3x=7.6-2.8 3x=4.8 x=4.8÷3 x=1.6 4x-1.5=10 解:4x=10+1.5 4x=11.5 x=11.5÷4 x=2.875 3(x-4.2)=12.9 解:x-4.2=12.9÷3 x-4.2=4.3 x=4.3+4.2 x=8.5

#include "stdafx.h"#include "iostream"#include "math.h"using namespace std;int _tmain(int argc, _TCHAR* argv[]){double x = 1.1;while(fabs(5*x*x*x-3*x*x+2*x-8)>0.000001)x = x - (5*x*x*x-3*x*x+2*x-8)/(15*x*x-6*x+2);cout

#include #include double root(double (*f)(double),double (*f1)(double), double x,double eps); double fx(double x){ return 2*x*x*x-4*x*x+3*x-6; } double fp(double x){ return 6*x*x-8*x+3; } int main() { double x=1.5,y,eps=1e-08; ...

3x+2x+1.5x=53.9 解:(3+2+1.5)x=53.9 6.5x=53.9 x=53.9÷6.5 x=8又19/65

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