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解方程(1)用因式分解法解:2x(x+5)=3(x+5)(...

2x(x-3)=5(3-x) 解:2x(x-3)-5(3-x)=0 2x(x-3)+5(x-3)=0 (2x+5)(x-3)=0 2x+5=0或x-3=0 x=-5/2或x=3 【学习宝典】团队为您答题。有不明白的可以追问!

(1)移项得:2x(x+5)-3(x+5)=0,分解因式得:(2x-3)(x+5)=0,可得2x-3=0或x+5=0,解得:x1=1.5,x2=-5;(2)方程变形得:x2-3x=4,配方得:x2-3x+94=254,即(x-32)2=254,开方得:x-32=±52,解得:x1=4,x2=-1;(3)方程整理得:2x...

(2x+3)²-(1-x)²=0 [(2x+3)-(1-x)][(2x+3)+(1-x)]=0 (3x+2)(x-4)=0 x1=-2/3,x2=4

(x+3)(x-1)=5 x²-x+3x-3-5=0 x²+2x-8=0 (x-2)(x+4)=0 x1=2, x2=-4

(1)方程变形得:(x-3)2+(x-3)=0,分解因式得:(x-3)(x-2)=0,可得x-3=0或x-2=0,解得:x1=3,x2=2;(2)开方得:x+3=2x-5或x+3=-2x+5,解得:x1=8,x2=23;(3)方程移项得:(3x-1)(x-1)-(4x+1)(x-1)=0,分解因式得:(x-1)...

(1)3(x-5)^2=2(5-x) 3(x-5)^2-2(5-x)=0 3(x-5)^2+2(x-5)=0 (x-5)[3(x-5)+2]=0 (x+5)(3x-13)=0 x=-5或x=13/3 (2)2(x-3)^2=9-x^2 2(x-3)^2-(9-x^2)=0 2(x-3)^2+(x^2-9)=0 2(x-3)^2+(x-3)(x+3)=0 (x-3)[2(x-3)+x+3]=0 (x-3)(3x-3)=0 (x-3)(...

(1)x2-4x+4=3,(x-2)2=3,x-2=±3,则x1=2+3,x2=2-3;(2)3(x-5)2+2(x-5)=0,(x-5)[3(x-5)+2]=0,x-5=0或3(x-5)+2=0,x1=5,x2=133.

(1)开方得:x-1=2或x-1=-2,解得:x1=3 x2=-1;(2)移项得:3(x-5)2+2(x-5)=0,分解因式得:(x-5)(3x-13)=0,解得:x1=5,x2=133.

(1)∵2x2-5x-4=0,∴2x2-5x=4,∴x2-52x=2,∴x2-52x+162516=2+2516,∴(x-54)2=5716,解得:x1=5+574,x2=5?574;(2)∵3(x-2)+x2-2x=0,∴3(x-2)+x(x-2)=0,∴(x-2)(3+x)=0,即x-2=0或3+x=0,解得:x1=2,x2=-3;(3)∵(a2-b2)x2-4ab...

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