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解方程(1)用因式分解法解:2x(x+5)=3(x+5)(...

2x(x-3)=5(3-x) 解:2x(x-3)-5(3-x)=0 2x(x-3)+5(x-3)=0 (2x+5)(x-3)=0 2x+5=0或x-3=0 x=-5/2或x=3 【学习宝典】团队为您答题。有不明白的可以追问!

解 (x-2)²=(2x+3)² x²-4x+4=4x²+12x+9 即 3x²+16x+5=0 (3x+1)(x+5)=0 ∴x=-5 或x=-1/3

(x+3)2-5(x+3)=0,(x+3)[(x+3)-5]=0,∴(x+3)=0或(x+3)-5=0,解得:x1=-3,x2=2.

(1)∵x 2 -4x=-1,∴x 2 -4x+4=3,∴(x-2) 2 =3,∴x-2=± 3 ,∴x 1 =2+ 3 ,x 2 =2- 3 ;(2)方程变形得3x 2 +10x+5=0,∵a=3,b=10,c=5,∴b 2 -4ac=10 2 -4×3×5=40,∴x= -10± 40 2×3 ,∴x 1 = -5+ 10 3 ,x 2 = -5- 10 3 ;(3)∵3(x-5) 2 ...

1.3(x-5)^2=(5+x)(5-x) 1.3(x-5)^2-(5+x)(5-x)=0 (x-5)(1.3(x-5)+1)=0 x-5=0或1.3(x-5)+1=0 x=5 x=55/13

3(x-5)^2=2(5-x) 3(x-5)^2-2(5-x)=0 3(x-5)^2+2(x-5)=0 (x-5)[3(x-5)+2]=0 (x-5)(3x-13)=0 x=5或x=13/3

(1)分解因式得:(x-1) 2 -2(x+1)(x-1)=0,(x-1)[(x-1)-2(x+1)]=0,x-1=0,(x-1)-2(x+1)=0,x 1 =1,x 2 =-3.(2)整理得:x 2 +2x-15=0,(x+5)(x-3)=0,x+5=0,x-3=0,x 1 =-5,x 2 =3.

2π=π^2+5π π^2+3π=0 π(π+3)=0 π=0或者π=-3

(1)方程变形得:(x-3)2+(x-3)=0,分解因式得:(x-3)(x-2)=0,可得x-3=0或x-2=0,解得:x1=3,x2=2;(2)开方得:x+3=2x-5或x+3=-2x+5,解得:x1=8,x2=23;(3)方程移项得:(3x-1)(x-1)-(4x+1)(x-1)=0,分解因式得:(x-1)...

把x+5看做一个整体, 原式=(x+5-3)2=(x+2)^2=0 所以x=-2

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