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解方程 x²-9x-36=0 3(x-2)²-12=0 x&#1...

1.2(x+5)²-12=0 (x+5)^2-6=0 (x+5+√6)(x+5-√6)=0 x1=-5-√6 x2=-5+√6 2. 2x²-3x-2=0 x^2-3x/2=1 (x-3/4)^2=25/16 x-3/4=土5/4 x1=2 x2=-1/2 3. 2x²-10x+52=0 x^2-5x+5/2=-52+25/4

解 x²-2√3x+1=0 x²-2√3x+3=2 (x-√3)²=2 ∴x-√3=±√2 ∴x=√3+√2 或x=√3-√2 2(x+3)²=2x+6 2(x+3)²-2(x+3)=0 (x+3)(2x+6-2)=0 (x+3)(2x+4)=0 ∴x=-3 或x=-2

两边乘以(x+2)(x-1)得 x(x-2)-(x²+x-2)=3 x²-2x-x²-x+2=3 -3x=1 ∴x=-1/3 检验:x=-1/3是方程的解

解: x-1/x+1+x-4/x+4=x-2/x+2+x-3/x+3 [(x-1)(x+4)+(x-4)(x+1)]/(x+1)(x+4)=[(x-2)(x+3)+(x-3)(x+2)]/(x+2)(x+3) (2x²-8)/(x+1)(x+4)=(2x²-12)/(x+2)(x+3) (x²-4)/(x²+5x+4)=(x²-6)/(x²+5x+6) (x²+5x+4)(x&...

4x²-6x=0, 2x(2x-3)=0, x1=0,x2=3/2, ———— x²+x-6=0, (x+3)(x-2)=0, x1=-3,x2=2, ———— (x-2)(x-3)=3, x²-5x+3=0, (x-5/2)²=13/4, x1=(5+√13)/2,x2=(5-√13)/2, ———— x²-2x-1=0, (x-1)&...

(x2-3x+2)(x2+3x-2)=x2(x+3)(x-3)? 应该是(x²-3x+2)(x²+3x-2)=x²(x+3)(x-3)吧? 解: (x²-3x+2)(x²+3x-2)=x²(x+3)(x-3) [x²-(3x-2)][x²+(3x-2)]=x²(x²-9) (x²)²-(3x-2)²=x&#...

解: 1. (x-1)(x-1-2)=0 x=1或3 2. (x+2+3)(x+2-3)=0 x=-5或1 3. 9(x-2)²-4(x+1)²=0 [3(x-2)+2(x+1)][3(x-2)-2(x+1)=0 (5x-4)(x-8)=0 x=4/5或8 4. 2(t-1)²+t-1=0 (t-1)[2(t-1)+1]=0 (t-1)(2t-1)=0 t=1或1/2

用十字相乘法分解因式 (2x+5)(x-2)=0 所以x=-5/2,x=2

1题x一5二土4,x二9或1。2是(x一2)^2二3,x二土v3十2。3是(x一3)(x十1)二0,x二3或一1。

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