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化简:(1)2(2a-3b)+3(2b-3a)(2)2(x2-xy)...

解:(1)原式=3a-2b+5a-7b-4a+8b =3a+5a-4a-2b-7b+8b=4a-b; (2)原式= - = + + -2 ;(3)原式=-x 2 +2xy-y 2 -2xy+6x 2 +6y-3xy=-x 2 +6x 2 +2xy-2xy-3xy-y 2 +6y 2 =5x 2 -3xy+5y 2 。

(1)原式=5a-3b-2a+4b=3a+b;(2)原式=(-3x2-xy-2y2)-(2x2+2xy-4y2)=-3x2-xy-2y2-2x2-2xy+4y2=-y2-3xy-2x2.

(1)a2?a3=a2+3=a5; (2)(x2y)4?xy-3=x8y4?xy-3=x9y;(3)(x-1)(x2+x+1)=x3+x2+x-x2-x-1=x3-1.故答案为:(1)a5;(2)x9y;(3)x3-1

如图

(1)①A+B+C=x2-3xy+y2-2xy-x2+2y2=-5xy+3y2;②2A-B-2C=2(x2-3xy)-(y2-2xy)-2(-x2+2y2)=2x2-6xy-y2+2xy+2x2-4y2=4x2-4xy-5y2;(2)2(3x2y-xy2)-(xy2+6x2y)+1=6x2y-2xy2-xy2-6x2y+1=-3xy2+1,∵|x-1|+(y+2)2=0,∴x=1,y=-2,则原式=-...

A=x2+xy+y2,B=-3xy-x2,(1)B-A=(-3xy-x2)-(x2+xy+y2)=-3xy-x2-x2-xy-y2=-2x2-4xy-y2;(2)2A-3B=2(x2+xy+y2)-3(-3xy-x2)=2x2+2xy+2y2+9xy+3x2=5x2+11xy+2y2;(3)由题意得:C=A-B=(x2+xy+y2)-(-3xy-x2)=x2+xy+y2+3xy+x2=2x2+4x...

(1)原式=x 2 +6xy+9y 2 +2x 2 -2xy+xy-y 2 =3x 2 +5xy+8y 2 ;(2)原式=x(x 2 -2xy+y 2 )=x(x-y) 2 ;(3)原式=-2y-x+5xy,当x=1,y=-3时,原式=6-1-15=-10.

x³+2a(x²+xy)-bx²-xy+y² =x³+(2a-b)x²+(2a-1)xy+y² x³、y²系数均不等于0,此两项恒存在,又得到的是三次二项式,因此化简后,(2a-b)x²、(2a-1)xy两项不存在,系数=0 2a-b=0 2a-1=0 解得a=1/2...

化简:(x+y)(x2-xy+y2) 解: 原式= :(x+y)(x2-xy+y2) =x*x^2-x*xy+xy^2+x^2y-xy^2+y^3 =x^3+y^3+(1-1)x^2y+(1-1)xy^2 =x^3+y^3 这个是立方和公式 立方差公式是: x^3-y^3 =(x-y)*(x^2-xy+y^2)

(1)=(x+y)(x-2y)-2x+7y-3 =(x+y-3)(x-2y+1) (2) =(a-1)(b-2) (3) =(x+m)(x+m+1) (4)(3x-1)(2x+m)=0 (5)(x-a)(x-a-2)

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