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3/2*5/7--5/7*5/2+-5/2*1/7等于多少(要过程

3/2*5/7-5/7*5/2-5/2*1/7 =3/2*5/7-5/7*5/2-5/7*1/2 =(3/2-5/2-1/2)*5/7 =-3/2*5/7 =-15/14

3/2 x 5/7 - (-5/7)x5/2 +(-1/2) 除以7/5 =3/2*5/7+5/7*5/2-1/2*5/7 =5/7*(3/2+5/2-1/2) =5/7*7/2 =5/2 =2又2分之1

3/2*5/7-(-5/7)*5/2+(-1/2)*7/5 =5/7×﹙3/2+5/2-1/2﹚ =5/7×7/2 =5/2

(-5)一(一1/2)+7-7/3 =-5+1/2+7-7/3 =5/2-7/3 =15/6-14/6 =1/6

3又1/2*(-5/7)-(-5/7)*2又1/2-5/7*(-1/2) =5/7×(-3又1/2+2又1/2+1/2) =5/7×(-1/2) =-5/14

原式=(-6/5)-(35/5)-(16/5)-(5/5)=(-6-35-16-5)/5=(-62)/5 =-12.4 原式=(-1.2)-7-(3.2)-1=-12.4

(-2.1)×6.5×(-3/7) =(-2.1)×(-3/7) ×6.5 =0.9×6.5 =5.85

是否满意?请采纳,谢谢

图片太小了,实在看不清。直接给出本题的程序: #include void main(){ double i,k=1,s=0; for(i=1;k>=1e-6;i++) {s+=k;k*=i/(i*2+1);} printf("%f",s*2); }

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