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(1) 3x^3-2x-1 (2)x^3+6x^2+11x+6 (3)x^4+2x^3-9x^...

(1) 3x^3-2x-1=(3x+1)(x-1) (2)x^3+6x^2+11x+6 =x^3+2x^2+4x^2+8x+3x+6 =x^2(x+2)+4x(x+2)+3(x+2) =(x+2)(x^2+4x+3) =(x+2)(x+1)(x+3) (3)x^4+2x^3-9x^2-2x+8 = x^4-2x^3+4x^3-8x^2-x^2+2x-4x+8 =x^3(x-2)+4x^2(x-2)-x(x-2)-4(x-2) =(x-2)(x^3+4...

原式=2(x³+1)-6x(x+1)=2(x+1)(x²-x+1)-6x(x+1)=2(x+1)(x²-x+1-3x)=2(x+1)(x²-4x+1)

1、原式=[(v3)^2-3]/[(v3)^4+(v3)^2+1] =0/(9+3+1)=0; 2、原式=limx→4{[v(2x+1)-3]*2(x-2-2)}/{[v(x-2)-v2]*(2x+1-9)} =lim2[v(x-2)+v2]/[v(2x+1)+3] =2[v(4-2)+v2]/[v(2*4+1)+3] =4v2/6 =2v2/3。

将分子分母同时除以 x^5, 得到原极限 =lim(x→∞) [(2-1/x)^2 * (3+2/x)^3] /(6+1/x)^5 那么在x趋于无穷大的时候, 1/x和2/x都是趋于0的, 于是就得到 原极限= 2^2*3^3 /6^5 =1/72

x1+x2+2X3+3X4=1 X1+3X2+6X3+X4=3 X1-5X2-10X3+9X4=a 增广矩阵= 1 1 2 3 1 1 3 6 1 3 1 -5 -10 9 a r2-r1,r3-r1 1 1 2 3 1 0 2 4 -2 2 0 -6 -12 6 a-1 r3+3r2,r2*(1/2),r1-r2 1 0 0 4 0 0 1 2 -1 1 0 0 0 0 a+5 所以 a=-5 时方程组有解 通解为 (...

(1)去括号得:6x-9+6x=6-x-2,移项合并得:13x=13,解得:x=1;(2)去分母得:12x-4-6x-3=12,移项合并得:6x=19,解得:x=196;(3)去括号得:3x+6-2x-4=2x+4,移项合并得:-x=2,解得:x=-2;(4)方程变形得:5x-20-2.5=20x-60,移项合并...

(x^2+3x+9)/(x^3-27)+(6x)/(9x-x^3)-(x-1)/(6+2x) =(x^2+3x+9)/[(x-3)(x^2+3x+9)]-6x/x(x²-9)-(x-1)/[2(x+3)] =1/(x-3)-6/(x+3)(x-3)-(x-1)/[2(x+3)] =2(x+3)/[2(x+3)(x-3)]-12/[2(x+3)(x-3)]-(x-1)(x-3)/[2(x+3)(x-3)] =(...

(1)原式=2(x+3)+2x?18?x?32(x+3)(x?3)=3x?152x2?18;(2)原式=x2+2x+4(x+2)2?3(x+2)2(x+2)(x?2)?(x+2)(x-2)=3x2+6x+122x+4.

(1)因式分解,得x(3x-6)=0,于是,得x=0,3x-6=0,x1=0,x2=2;(2)因式分解,得,(x-1+x)(x-1-x)=0,于是,得,x-1+x=0,x-1-x=0,x=12;(3)移项,得(x+1)2-(2x-1)2=0,因式分解得,(x+1+2x-1)(x+1-2x+1)=0,于是,得3x=0,...

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