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因式分解:(x⁴+x²-4)(x⁴+x²...

解: x¹⁷-x =x(x¹⁶-1) =x(x⁸-1)(x⁸+1) =x(x⁴-1)(x⁴+1)(x⁸+1) =x(x²-1)(x²+1)(x⁴+1)(x⁸+1) =x(x-1)(x+1)(x²+1)(x⁴+1)(x⁸+1)

最后为6,前面为6,推测因式分解中有2x²+ax+3或3x²+bx+2,得(2x²+ax+3)*(3x²+bx+2)=6x⁴+(3a+2b)x³+(4+ab+9)x²+(2a+3b)x+6有3a+2b=713+ab=-362a+3b=-7求解得a=7b=-7因此6x⁴+7x³-36x²-7x+6=(...

2x^5+7x⁴+12x³+14x²+10x+3 =2x^5+2x⁴+5x^4+5x³+7x³+7x²+7x²+7x+3x+3 =2x⁴(x+1)+5x³(x+1)+7x²(x+1)+7x(x+1)+3(x+1) =(x+1)(2x⁴+5x³+7x²+7x+3) =(x+1)(2x⁴+2x&#...

x⁵-6x⁴+12x³-12x²+11x-6 =x⁵-x⁴-5x⁴+5x³+7x³-7x²-5x²+5x+6x-6 =x⁴(x-1)-5x³(x-1)+7x²(x-1)-5x(x-1)+6(x-1) =(x-1)(x⁴-5x³+7x²-5x+6) =(x-1)(x...

1-x⁸ =(1+x⁴)(1-x⁴) =(1+x⁴)(1+x²)(1-x²) =(1+x⁴)(1+x²)(1+x)(1-x)

实数范围内因式分解: x⁵-x³y²-12xy⁴ =x(x⁴-x²y²-12y⁴) =x(x²-4y²)(x²+3y²) =x(x+2y)(x-2y)(x²+3y²) 如果是复数范围内因式分解,那么: x⁵-x³y²-12...

确定最后一项是- 吗?这样的话没法分解啊,我下面按照+分解,不明白欢迎追问! 解: 利用换元法 设x+y=a,x-y=b,则 (x+y)^4+(x^2-y^2)^2+(x-y)^4 =a⁴+(ab)²+b⁴ =a⁴+2a²b²+b⁴-a²b² =(a²+...

9-x²-y²+2xy =9-(x²-2xy+y²) =9-(x-y)² =[3+(x-y)][3-(x-y)] =(3+x-y)(3-x+y) x⁴+x²y²+y⁴ =x⁴+2x²y²+y⁴-x²y² =(x²+y²)²-(xy)² =(x²+...

a⁴+b⁴+c⁴-2a²b²-2a²c²+2b²c² =(b⁴+2b²c²+c⁴)-2a²(b²+c²)+a⁴ =(b²+c²)²-2a²(b²+c²)+a⁴ =(b²+c...

2a的4次方-a的3次方-6a的2次方-a+2要求因式分解 解: 2a⁴-a³-6a²-a+2 =(2a⁴-a³)-(6a²+a-2) =a³(2a-1)-(2a-1)(3a+2) =(2a-1)(a³-3a-2)

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