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一加二分之一的和乘以一加三分之一的和乘以一加四...

(1+1/2)x(1+1/3)x(1+1/4)x...x(1+1/10) =3/2x4/3x5/4x....x11/10 =11/2 =5.5 , 你好,本题已解答,如果满意 请点右下角“采纳答案”。

解:原题就是:1+1/2+1/3+1/4+......+1/n的极限。 因为 (1+1/2)+(1/3+1/4)+(1/5+1/6)+…… >(1/2+1/2)+(1/4+1/4)+(1/6+1/6)+…… =1+1/2+1/3+…… 可以看出,一个数会大于它本身,产生矛盾,所以它的极限是无穷大的,或者说是无极限。

13/2 解析: 规律:1+1/n=(n+1)/n 所以, 原式 =(3/2)*(4/3)*(5/4)*....*(13/12) =13/2

(1+1/2)×(1+1/23)×(1+1/3)×……×(1+1/18)×(1+1/19)×(1+1/20)=3/2×4/3×5/4×……×19/18×20/19×21/20 =21/2 =10.5

1x1/2+2x1/3+3×1/4+4x1/5 =1/2+2/3+3/4+4/5 =30/60+40/60+45/60+28/60 =143/60 =2又23/60

如图

(1+1/2)×(1+1/3)×(1+1/4)×……×(1+1/10) =(2/2+1/2)×(3/3+1/3)×(4/4+1/4)×……×(10/10+1/10) =3/2×4/3×5/4×……×11/10 =11/2 =5.5

(1/2+1/3+1/4)x120=60+40+30=130

1/2×3+1/3×4+1/4×5+……+1/2015×2016 =1/2-1/3+1/3-1/4+1/4-1/5+……+1/2015-1/2016 =1/2-1/2016 =1007/2016

(1+1/2)×(1+1/2的2次方)×(1+1/2的4次方)×(1+1/2的8次方)+1/2的15次方 =(1-1/2)(1+1/2)×(1+1/2的2次方)×(1+1/2的4次方)×(1+1/2的8次方)/(1-1/2)+1/2的15次方 =(1-1/2的2次方)×(1+1/2的2次方)×(1+1/2的4次方)×(1+1/2的...

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