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用适当的方法解下列方程:(1)3x 2 -6=0;(2)x ...

(1)x2=2,x1=2,x2=-2;(2)x(x-5)=0,∴x=0或x-5=0,∴x1=0,x2=5;(3)∵△=25-4×2=17,∴x=5±172×2,∴x1=5+174,x2=5?174;(4)∵(3x-1+2x)(3x-1-2x)=0,∴3x-1+2x=0或3x-1-2x=0,∴x1=15,x2=1.

(1)3x 2 =27x 2 =9x 1 =3或x 2 =-3;(2)b 2 -4ac=(-2) 2 -4×1×(-1)=8x= (-2)± 8 2 = 2±2 2 2 x 1 =1+ 2 或x 2 =1- 2 ;(3)(x-6)(2x+1)=0x-6=0或2x+1=0x 1 =6或x 2 =- 1 2

(1)x2-3x-2=0,△=(-3)2-4×1×(-2)=17,所以x=3±172×1,所以x1=3+172,x2=3?172;(2)(x-2)(x-3)=0,x-2=0或x-3=0,所以x1=2,x2=3;(3)(3x+1)2-4(x-2)2=0,(3x+1+2x-4)(3x+1-2x+4)=0,3x+1+2x-4=0或3x+1-2x+4=0,所以x1=3...

(1)(x+1)2=3,x+1=±3,∴x1=-1-3,x2=-1+3;(2)(x+1)(x+2)=6,x2+3x+2-6=0,即x2+3x-4=0,∴(x+4)(x-1)=0,∴x1=-4,x2=1;(3)(x-2)2=3x(x-2),(x-2)(-2x-2)=0,∴x1=2,x2=-1.

(1)49(x-3)2=16(x+6)249(x-3)2-16(x+6)2=0【7(x-3)+4(x+6)】【7(x-3)-4(x+6)】=0所以7(x-3)+4(x+6)=0,7(x-3)-4(x+6)=0,解得∴x1=-311,x2=15;(2)(2-3x)(x+4)=(3x-2)(1-5x)(2-3x)(x+4)+(2-3x)(1-5x...

解:(1)开方得:3x﹣1=2(x+2),3x﹣1=﹣2(x+2),3x﹣1=2x+2,3x﹣1=﹣2x﹣4,3x﹣2x=2+1,3x+2x=﹣4+1,解方程得:x 1 =3,x 2 =﹣ 。(2)分解因式得:(2x﹣1)(x﹣1)=0,2x﹣1=0,x﹣1=0,解得:x 1 = ,x 2 =1。(3)移项得:x 2 ...

(1)移项得:x 2 -3x=0,分解因式得:x(x-3)=0,x=0,x-3=0,解得:x 1 =0,x 2 =3; (2)设 x 2 -2 x+1 =y,则原方程化为y+ 8 y +6=0,y 2 +6y+8=0,(y+4)(y+2)=0,y 1 =-4,y 2 =-2,当y=-4时, x 2 -2 x+1 =-4,即x 2 +4x+2=0,x= -...

(3x-4)的平方=(3-4x)的平方 所以3x-4的绝对值=3-4x绝对值 3x-4=3-4x或者3x-4=4x-3 x=1或者-1 5(x+6)(x-1)+4x(x-1)=3x(x+6) 5(x^2+5x-6)+4x^2-4x=3x^2+18x 2x^2+x-10=0 x=2或者-5/2 希望能帮助到你!

第四题:x²-2x+1=1,(x-1)²=1,x=2或0

(1)(x-3)(x+7)=-9 x^2+4x-21+9=0 (x-2)(x+6)=0 x=2或x=-6 (2)x²-3x-10=0 (x-5)(x+2)=0 x=5或x=-2 (3)(2y+1)²-8(2y+1)+15=0 (2y+1-3)(2y+1-5)=0 y=1或y=2 (4)(x-√3)=√2x(x-√3) (x-√3)-√2x(x-√3)=0 (x-√3)(1-√...

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