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用适当的方法解下列方程:(1)49(x-3)2=16(x+6...

(1)49(x-3)2=16(x+6)249(x-3)2-16(x+6)2=0【7(x-3)+4(x+6)】【7(x-3)-4(x+6)】=0所以7(x-3)+4(x+6)=0,7(x-3)-4(x+6)=0,解得∴x1=-311,x2=15;(2)(2-3x)(x+4)=(3x-2)(1-5x)(2-3x)(x+4)+(2-3x)(1-5x...

(1)∵(3x-1)2=49,∴3x-1=±7,∴3x-1=7,3x-1=-7,解得:x1=83,x2=-2;(2)∵3x2+4x-7=0,∴(3x+7)(x-1)=0,即3x+7=0或x-1=0,解得:x1=-73,x2=1;(3)∵(x-3)(x+2)=6,∴x2-x-12=0,∴(x+3)(x-4)=0,解得:x1=-3,x2=4;(4)∵3(x...

(1)x2-x-1=0,△=1-4×(-1)=5,x=1±52,所以x1=1+52,x2=1?52;(2)(2x-3)2-(x+6)2=0,(2x-3+x+6)(2x-3-x-6)=0,2x-3+x+6=0或2x-3-x-6=0,所以x1=-1,x2=9;(3)x2-3x+2=0,(x-1)(x-2)=0,x-1=0或x-2=0,所以x1=1,x2=2.

(1)因式分解得,(2x+1)(x+3)=0,解得,x1=12,x2=3;(2)移项得,(x-1)2+2(x-1)=0,提公因式得,(x-1)(x-1+2)=0,解得,x1=1,x2=-1;(3)移项得,x(2x+3)-(4x+6)=0,提公因式得,(2x+3)(x-2)=0,解得,x1=-32;x2=2;...

(1)4(x-3)2=25x-3=±52x=3±52∴x1=112,x2=12.(2)(x-4)(x+3)=0∴x1=4,x2=-3.(3)(2x+1-6)(2x+1+1)=0(2x-5)(2x+2)=0∴x1=52,x2=-1.(4)方程整理得:x2-4x-1=0a=1,b=-4,c=-1,△=16+4=20x=4±202,∴x1=2+5,x2=2-5.

令y=x-2,则y²-6y+9=0,即(y-3)²=0 ∴y=3即x-2=3,x=5

解:3(x+2)=4(x+1) 3x+6=4x+4 4x-3x=6-4 x=2 希望能够帮助你

4、(2x+1)(x-1)=0 2x+1=0,x1=-1/2 x-1=0,x2=1

解:(1)9-6x+x 2 +x 2 =9 2x 2 -6x=0 2x(x-3)=0则x 1 =0,x 2 =3;(2)令1-2x=t则原式=t 2 +t-6=0(t+3)(t-2)=0则t 1 =-3,t 2 =2若t 1 =-3,则1-2x=-3则x 1 =2若t 2 =2,则1-2x=2则x 2 =- ;(3)9x 2 -6x+1=4(1-2x+x 2 ) 9x 2 -6x+...

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